In Python, a string of text can be aligned left, right and center.
.ljust(width)
This method returns a left aligned string of length width.
>>> width = 20
>>> print 'HackerRank'.ljust(width,'-')
HackerRank----------
.center(width)
This method returns a centered string of length width.
>>> width = 20
>>> print 'HackerRank'.center(width,'-')
-----HackerRank-----
.rjust(width)
This method returns a right aligned string of length width.
>>> width = 20
>>> print 'HackerRank'.rjust(width,'-')
----------HackerRank
Task
You are given a partial code that is used for generating the HackerRank Logo of variable thickness.
Your task is to replace the blank (______) with rjust, ljust or center.
Input Format
A single line containing the thickness value for the logo.
Constraints
The thickness must be an odd number.
Output Format
Output the desired logo.
Sample Input
5
Sample Output :- please refer hackerrank
Solution :-
#Replace all ______ with rjust, ljust or center. thickness = int(input()) #This must be an odd numberc = 'H'#Top Conefor i in range(thickness): print((c*i).rjust(thickness-1)+c+(c*i).ljust(thickness-1))#Top Pillarsfor i in range(thickness+1): print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6))#Middle Beltfor i in range((thickness+1)//2): print((c*thickness*5).center(thickness*6)) #Bottom Pillarsfor i in range(thickness+1): print((c*thickness).center(thickness*2)+(c*thickness).center(thickness*6)) #Bottom Conefor i in range(thickness): print(((c*(thickness-i-1)).rjust(thickness)+c+(c*(thickness-i-1)).ljust(thickness)).rjust(thickness*6))

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